1890 Rhode Island gubernatorial election
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| Elections in Rhode Island |
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The 1890 Rhode Island gubernatorial election was held on April 2, 1890. Democratic nominee John W. Davis defeated incumbent Republican Herbert W. Ladd with 48.76% of the vote.
General election
Candidates
Major party candidates
- John W. Davis, Democratic
- Herbert W. Ladd, Republican
Other candidates
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | John W. Davis | 20,548 | 48.76% | ||
| Republican | Herbert W. Ladd (incumbent) | 18,988 | 45.06% | ||
| Prohibition | John H. Larry | 1,820 | 4.32% | ||
| Independent | Arnold B. Chace | 752 | 1.78% | ||
| Majority | 1,560 | ||||
| Turnout | |||||
| Democratic gain from Republican | Swing | ||||
References
- ^ "A Quaker for Governor". The sun. New York, N.Y. March 2, 1890. p. 18. Retrieved January 9, 2021.
- ^ "For the Suppression of Rum". Pittsburg dispatch. Pittsburg, Pa. February 26, 1890. p. 4. Retrieved January 9, 2021.
- ^ "Personal and Political". The herald. Milbank, S.D. March 4, 1890. p. 2. Retrieved January 9, 2021.
- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 27, 2020.
Categories:
- Articles with short description
- Short description with empty Wikidata description
- Use mdy dates from September 2023
- Rhode Island gubernatorial elections
- 1890 United States gubernatorial elections
- 1890 Rhode Island elections
- April 1890 events
- 1890 in Rhode Island
- United States gubernatorial elections in the 1890s