1877 Iowa gubernatorial election

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1877 Iowa gubernatorial election

← 1875

October 9, 1877

1879 →


Nominee	John H. Gear	John P. Irish	Daniel P. Stubbs
Party	Republican	Democratic	Greenback
Popular vote	121,316	79,304	34,316
Percentage	49.39%	32.29%	13.97%

Governor before election

Joshua G. Newbold
Republican

Elected Governor

John H. Gear
Republican

Federal government

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The 1877 Iowa gubernatorial election was held on October 9, 1877. Republican nominee John H. Gear defeated Democratic nominee John P. Irish with 49.39% of the vote.

General election

Candidates

Major party candidates

John H. Gear, Republican
John P. Irish, Democratic

Other candidates

Daniel P. Stubbs, Greenback
Elias Jessup, Prohibition

Results

1877 Iowa gubernatorial election^[1]
Party		Candidate	Votes	%	±%
	Republican	John H. Gear	121,316	49.39%
	Democratic	John P. Irish	79,304	32.29%
	Greenback	Daniel P. Stubbs	34,316	13.97%
	Prohibition	Elias Jessup	10,565	4.30%
Majority			42,012
Turnout
	Republican hold		Swing

References

^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved September 21, 2020.

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