1844 United States presidential election in Pennsylvania
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Elections in Pennsylvania |
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Government |
The 1844 United States presidential election in Pennsylvania took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for the Democratic candidate, James K. Polk, over the Whig candidate, Henry Clay. Polk won Pennsylvania by a narrow margin of 1.91%.
Results
1844 United States presidential election in Pennsylvania[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | James K. Polk | 167,447 | 50.50% | 26 | |
Whig | Henry Clay | 161,125 | 48.59% | 0 | |
Liberty | James G. Birney | 3,000 | 0.90% | 0 | |
Totals | 331,572 | 100.0% | 26 |
See also
References
- ^ "1844 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.
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