1801 United States Senate election in Pennsylvania
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102 Members of the Pennsylvania legislature Plurality of votes needed to win | |||||||||||||||||
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| Elections in Pennsylvania |
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 Government |
The 1801 United States Senate election in Pennsylvania was held on February 19, 1801. Peter Muhlenberg was elected by the Pennsylvania General Assembly to the United States Senate.[1]
Results
Incumbent Federalist William Bingham, who was elected in 1795, was not a candidate for re-election to another term. The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on February 19, 1801, to elect a new Senator to fill the term beginning on March 4, 1801. Two ballots were recorded. The results of the second and final ballot of both houses combined are as follows:
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Peter Muhlenberg | 46 | 45.10 | |
| Democratic-Republican | George Logan | 45 | 44.12 | |
| Not voting | 11 | 10.78 | ||
| Total votes | 102 | 100 | ||
References
- ^ a b "U.S. Senate Election - 19 February 1801" (PDF). Wilkes University. Retrieved September 28, 2013.