1826 New Hampshire gubernatorial election
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The 1826 New Hampshire gubernatorial election was held on 14 March 1826 in order to elect the Governor of New Hampshire. Incumbent Democratic-Republican Governor David L. Morril defeated former Democratic-Republican member of the New Hampshire House of Representatives Benjamin Pierce.[1]
General election
On election day, 14 March 1826, incumbent Democratic-Republican Governor David L. Morril won re-election by a margin of 5,291 votes against his opponent Democratic-Republican candidate Benjamin Pierce, thereby retaining Democratic-Republican control over the office of Governor. Morril was sworn in for his third term on 7 June 1826.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | David L. Morril (incumbent) | 17,578 | 58.08 | |
| Democratic-Republican | Benjamin Pierce | 12,287 | 40.59 | |
| Scattering | 403 | 1.33 | ||
| Total votes | 30,268 | 100.00 | ||
| Democratic-Republican hold | ||||
References
- ^ "David L. Morril". National Governors Association. Retrieved 1 April 2024.
- ^ "NH Governor". ourcampaigns.com. 2 June 2005. Retrieved 1 April 2024.
Categories:
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- New Hampshire gubernatorial elections
- 1826 United States gubernatorial elections
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