1788–89 United States presidential election in New Hampshire
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Elections in New Hampshire |
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The 1788–89 United States presidential election in New Hampshire took place on January 7, 1789, as part of the 1788–89 United States presidential election to elect the first President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire unanimously voted for independent candidate and commander-in-chief of the Continental Army, George Washington. The total vote is composed of 5,909 for Federalist electors, all of whom were supportive of Washington.
Results
1788-1789 United States presidential election in New Hampshire | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Independent | George Washington | 5,909 | 100.00% | 5 | |
Totals | 5,909 | 100.00% | 5 |
See also
References
Categories:
- Articles with short description
- Short description matches Wikidata
- Use mdy dates from September 2023
- Elections using electoral votes
- 1788–1789 United States presidential election by state
- United States presidential elections in New Hampshire
- 1789 New Hampshire elections
- All stub articles
- New Hampshire election stubs