1890 Serbian parliamentary election
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Parliamentary elections were held in Serbia on 14 September 1890 to elect members of the National Assembly. The result was a landslide victory for the People's Radical Party.
Background
The elections were the first held under the 1888 constitution.[1] Following the introduction of the new constitution, an Electoral Act was passed in March 1890, which provided for nearly universal male suffrage and introduced the secret ballot.[2]
Results
The People's Radical Party won over 100 seats, while the Liberal Party won 14 and the Serbian Progressive Party just one (won by its leader Milutin Garašanin).[1]
| Party | Votes | % | Seats | |
|---|---|---|---|---|
| People's Radical Party | 152,935 | >100 | ||
| Liberal Party | 23,548 | 14 | ||
| Serbian Progressive Party | 8,895 | 1 | ||
| Total | ||||
| Source: Protić | ||||
Aftermath
Nikola Pašić was appointed president of the National Assembly and Dimitrije Katić as vice president.[1] When Pašić became Prime Minister in February 1891, Katić replaced him as president while Pavle Vuković became vice president.
References
- ^ a b c Cedomil Mitrinović and Milos N. Brasić (1937). "Yugoslavian National Assembly and Parliaments". pp. 137–141.
- ^ Milan St. Protić (2015). Between democracy and populism: Political ideas of the People's Radical Party in Serbia (the formative period: 1860s to 1903) (PDF). p. 54.
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