1813 Georgia gubernatorial election
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| Elections in Georgia |
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The 1813 Georgia gubernatorial election was held on 5 November 1813 in order to elect the Governor of Georgia. Democratic-Republican candidate and former member of the U.S. House of Representatives from Georgia's at-large congressional district Peter Early defeated fellow Democratic-Republican candidate John Clark in a Georgia General Assembly vote.[1]
General election
On election day, 5 November 1813, Democratic-Republican candidate Peter Early won the election against his opponent fellow Democratic-Republican candidate John Clark. Early was sworn in as the 28th Governor of Georgia on 5 November 1813.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Peter Early | 66 | 55.93 | |
| Democratic-Republican | John Clark | 48 | 40.68 | |
| Nicholas Long | 4 | 3.39 | ||
| Total votes | 118 | 100.00 | ||
| Democratic-Republican hold | ||||
References
- ^ "Georgia 1813 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University. Retrieved 8 December 2023.
- ^ "GA Governor". ourcampaigns.com. 18 July 2022. Retrieved 8 December 2023.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
Categories:
- Georgia (U.S. state) gubernatorial elections
- 1813 United States gubernatorial elections
- 1813 Georgia (U.S. state) elections
- November 1813 events
- 1813 in Georgia (U.S. state)
- Indirect elections
- 1810s in Georgia (U.S. state)
- 1810s Georgia (U.S. state) elections
- 1813 elections
- 1813 elections in North America
- 1813 elections in the United States
- United States gubernatorial elections in the 1810s
- Government of Georgia (U.S. state)