1804 United States presidential election in Massachusetts
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This article relies largely or entirely on a single source. (July 2023) |
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Elections in Massachusetts |
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The 1804 United States presidential election in Massachusetts took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. Voters chose 17 representatives, or electors to the Electoral College, who voted for president and Vice President.
During this election, the Federalist Party continued to lose ground as incumbent president Thomas Jefferson won all 17 Massachusetts state electors by a narrow margin of 7.16%. Jefferson would end up as the winner of the 1804 United States presidential election in a landslide victory.
Results
1804 United States presidential election in Massachusetts[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Thomas Jefferson (incumbent) | 29,599 | 53.58% | 17 | |
Federalist | Charles C. Pinckney | 25,644 | 46.42% | 0 | |
Totals | 55,243 | 100.0% | 17 |
1804 Vice Presidential Electoral Vote[1] | |||||
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Party | Candidate | Electoral votes | |||
Democratic-Republican | George Clinton (incumbent) | 17 | |||
Federalist | Rufus King | 0 | |||
Totals | 17 |
See also
References
- ^ a b "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 4, 2023.
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